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Solve the equation: $$\sqrt{2}x-\sqrt{2}=-2\sqrt{2}$$
\(x=-\sqrt{2}\)
\(x=\sqrt{2}\)
\(x=1\)
\(x=-1\)
Explanation
Add \(\sqrt{2}\) to both sides of the equation: $$\sqrt{2}x-\sqrt{2}+\sqrt{2}=-2\sqrt{2}+\sqrt{2}$$ $$\sqrt{2}x=-\sqrt{2}$$ Divide both sides of the equation by \(\sqrt{2}\): $$x=-1$$
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